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So our equation for the launch angle of the projectile is 𝜃 equals the inverse sin of the square root of two 𝑔ℎ divided by 𝑉. All that's left to do is to substitute our known values of 𝑉, 𝑔, and ℎ into this equation to calculate 𝜃. The question tells us that the initial speed of the projectile is 28 meters per second.

1:17 6:53 Projectile Motion - Calculating Launch Velocity - YouTube YouTube Start of suggested clip End of suggested clip Negative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u inMoreNegative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u in the Y. Direction.

The maximum height of an object, given the initial launch angle and initial velocity is found with: ｈ=v2isin2θi2g. The time of flight of an object, given the initial launch angle and initial velocity is found with: T=2visinθg .

1:32 6:53 Projectile Motion - Calculating Launch Velocity - YouTube YouTube Start of suggested clip End of suggested clip Negative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u inMoreNegative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u in the Y.

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

Angle-launched projectiles are objects projected at an angle to the horizontal. Their motion begins with both an x- and y-velocity component. Projectiles have no horizontal acceleration and a vertical acceleration of 9.8 m/s/s, ↓. At the highest point (the “peak”), the vertical velocity is 0 m/s.

The elementary trigonometric identity sin2θ+cos2θ=1 for all θ∈R can then be employed to obtain the launch speed v and the launch angle from the definition tanα=vsinαvcosα.

Launch Velocity Formula To calculate launch velocity, multiply the change in horizontal distance by the square root of g over 2 times the height.

So our equation for the launch angle of the projectile is 𝜃 equals the inverse sin of the square root of two 𝑔ℎ divided by 𝑉. All that's left to do is to substitute our known values of 𝑉, 𝑔, and ℎ into this equation to calculate 𝜃. The question tells us that the initial speed of the projectile is 28 meters per second.

1:17 6:53 Projectile Motion - Calculating Launch Velocity - YouTube YouTube Start of suggested clip End of suggested clip Negative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u inMoreNegative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u in the Y. Direction.

The maximum height of an object, given the initial launch angle and initial velocity is found with: ｈ=v2isin2θi2g. The time of flight of an object, given the initial launch angle and initial velocity is found with: T=2visinθg .

1:32 6:53 Projectile Motion - Calculating Launch Velocity - YouTube YouTube Start of suggested clip End of suggested clip Negative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u inMoreNegative 30 is equal to U in the Y direction which is what we're trying to find. So this is a u in the Y.

The sine function reaches its largest output value, 1, with an input angle of 90 degrees, so we can see that for the longest-range punts 2θ = 90 degrees and, therefore, θ = 45 degrees. A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.

Angle-launched projectiles are objects projected at an angle to the horizontal. Their motion begins with both an x- and y-velocity component. Projectiles have no horizontal acceleration and a vertical acceleration of 9.8 m/s/s, ↓. At the highest point (the “peak”), the vertical velocity is 0 m/s.

The elementary trigonometric identity sin2θ+cos2θ=1 for all θ∈R can then be employed to obtain the launch speed v and the launch angle from the definition tanα=vsinαvcosα.

Launch Velocity Formula To calculate launch velocity, multiply the change in horizontal distance by the square root of g over 2 times the height.